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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
高中數學方程式問題(20點)
Jul 17th 2013, 02:43

題目是這樣的，我想請大大看看哪錯了?? (順便給正解的算式)
a.b為實數，3a+2b+6ab=9a²+4b²+1 ，求對數(a,b)

我的算是為下:
9a²-3a+4b²-2b-6ab+1=0
9a²-(6b+3)a+(4b²-2b+1)=0

a=(6b+3±根號((6b+3)²-4*9*(4b²-2b+1)))/18-------------1
化減後為a=2b+1±根號(-12b²+12b-3)/6
因為a為實數所以根號中為0
解-12b²+12b-3=0
得b=(1+根號2)/2
帶入1式得a=(2+根號2)/6

解果答案不對(答案好像是(1/2，1/3)還是(1/3，1/2)吧)

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