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O為圓心, QR//PO, 求角OPR
Aug 21st 2013, 04:30

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O=圓心, QR//PO, ∠POQ=2x, ∠OSP=3x, 求∠OPR=y=? Ans: OQ與PR交點=S OP//QR: ∠OPR=∠PRQ=y 連接OR: ΔPOR=等腰Δ(OP=OR) = ∠OPR=∠ORP=y ΔOQR=等腰Δ(OQ=OR) = ∠OQR=∠ORQ=2x=2y 得到: y=x ΔOPS裡面: x+2x+3x=180 = x=y=30(deg)...
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